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Give an example of a preorder \((P,\le)\) and a subset \(A\) of its elements such that \(A\) has more than one meet. In fact, give an example in which \(P\) only has two elements.
Comments
Let \(a,b \in P\) and subset \(A = \{ a \leq b \; and \; b \leq a \}\). Then you get two meets namely, \(a \wedge b = a\) and \(b \wedge a = b\)?
Using reflexivity and transitivity, we can expand this out into a transitivity triangle and get 1. \(a \leq b \leq a\) and \(a \leq a\) and 2. \(b \leq a \leq b\) and \(b \leq b\). Taking \(a \wedge b\) in Triangle 1 and Triangle 2 gives a and b respectively.
Let \\(a,b \in P\\) and subset \\(A = \\{ a \leq b \; and \; b \leq a \\}\\). Then you get two meets namely, \\(a \wedge b = a\\) and \\(b \wedge a = b\\)? Using reflexivity and transitivity, we can expand this out into a transitivity triangle and get 1. \\(a \leq b \leq a\\) and \\(a \leq a\\) and 2. \\(b \leq a \leq b\\) and \\(b \leq b\\). Taking \\(a \wedge b\\) in Triangle 1 and Triangle 2 gives a and b respectively.