1. The products of identity morphism for pairs of objects, one from \\(\mathcal {C}\\) and the other from \\(\mathcal {D}\\).

2. Because composition in each multiplicand is associative.

3. It has objects \\((1,a)\\), \\((1,b)\\), and a single non-identity morphism: \\((\mathrm{id}_1,f):(1,a)\to(1,b)\\).

4. It is the product preorder on the Cartesian product of the underlying sets (since \\((f,g):(c,d)\to(c',d')\\) exists iff there is a morphism from \\(c\\) to \\(c'\\) and a morphism from \\(d\\) to \\(d'\\), i.e., products are ordered iff both their multiplicands are (as in Example 1.47)).