Azimuth Forum
Visit Site
@Igor – here's a one-line answer to **Puzzle 278**:
\\((f\otimes g)\circ(f'\otimes g') = \otimes(f, g)\circ\otimes(f', g') = \otimes((f, g)\circ(f', g')) = \otimes(ff', gg') = ff'\otimes gg'\\)
Version 2.1.8p2