Well this completely generalizes to the vector-case, and the solution to the master equation is written exactly the same way

\\[\Gamma(t) = e^{H t}\ \Gamma(0)\\]

Now, the constant \\(H\\) is the matrix for the linear operator.

\\[\Gamma(t) = e^{H t}\ \Gamma(0)\\]

Now, the constant \\(H\\) is the matrix for the linear operator.